import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;

/**
 * @author: gao
 * @create-date: 2025/3/3 10:39
 */

public class Solution {
    public List<Integer> findAnagrams(String s, String p) {
        List<Integer> ret = new ArrayList<>();
        char[] ss = s.toCharArray();
        char[] pp = p.toCharArray();

        int[] hash1 = new int[26]; // 统计p中每一个字符出现的个数
        for (char ch : pp) hash1[ch - 'a']++;

        int[] hash2 = new int[26]; // 统计窗口中字符出现的个数
        for (int left = 0, right = 0, count = 0; right < s.length(); right++) {
            char in = ss[right];
            if (++hash2[in - 'a'] <= hash1[in - 'a']) count++; // 进窗口与维护count
            if (right - left + 1 > p.length()) { // 判断
                char out = ss[left++];
                if (hash2[out - 'a']-- <= hash1[out - 'a']) count--; // 出窗口与维护count
            }
            if (count == p.length()) ret.add(left);
        }
        return ret;
    }

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        while(in.hasNextLine()){
            String s = in.nextLine();
            String p = in.nextLine();
            Solution solution = new Solution();
            List<Integer> result = solution.findAnagrams(s,p);
            System.out.println(result);
        }
    }
}